Question
In a group of 50 students, the average monthly tuition
is Rs. 7,200. Following a fee adjustment, the new average monthly tuition per student is Rs. (7200 + X). If the combined tuition fees for all students after the fee adjustment amount to Rs. 3,85,000, find the value of (X + 30% of X).Solution
ATQ, Initial total tuition for all 50 students = 50 X 7200 = 3,60,000 New total tuition for all 50 students = Rs. 3,85,000 Increase in tuition = 385000 - 360000 = Rs. 25,000 So, X = (25000/50) = 500 So, X + 30% of X = 500 + 0.30 X 500 = 500 + 150 = 650
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
(i) 2x² – 9x + 10 = 0
(ii) 4y² – 12y + 9 = 0
I). 5p2 Â - p - 4 = 0
II). q2 - 12q + 27 = 0
I. x2 – 19x + 88 = 0
II. (y + 4)2 = 121
I. 27x6-152x3+125=0
II. 216y6Â -91y3+8=0
I. p² - 10p +21 = 0
II. q² + q -12 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 31x² - 170x + 216 = 0
Equation 2: 22y² - 132y + ...
i) p2+p=56 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
II) q2-17q+72=0
...Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 38x + 352 = 0
Equation 2: y² - 38y + 312 = 0
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
