Question
Average of three consecutive numbers is 91. Find the sum
of smallest and largest number.Solution
Let the numbers be (a - 1), a and (a + 1).
So, (a - 1 + a + a + 1) ÷ 3 = 91
Or, (3a/3) = 91
Or, 'a' = 91
Required sum = a - 1 + a + 1 = 2a = 2 × 91 = 182
More Average Questions
I. x2 + 25x + 154 = 0
II. y2 + 27y + 181 = 0
I. 2b2 - 37b + 143 = 0
II. 2a2 + 15a - 143 = 0
l). 3p + 2q = 27
ll). 4p - 3q = 2
I. x3 = 1728
II. y2 – 15y + 56 = 0
I. x2 - 17x + 70 = 0
II. y2 - 11y + 28 = 0
I. 12 x ² - 3 x – 15 = 0
II. 2 y² + 12
I. 3p² - 11p + 10 = 0
II. 2q² + 13q + 21 = 0
I. 2y2Â + 11y + 15 = 0
II. 3x2Â + 4x - 4= 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 11x² - 93x + 88 = 0
Equation 2: 13y² + 118y + 93 = 0
I. 5x2 – 18x + 16 = 0
II. 3y2 – 35y - 52 = 0
