Question
A man earns 7/4 times in March, May, July, and December
than his average earning of ₹ 8000 per month in the rest of the months. So his savings in the March, May, July, and December goes to 3/2 times than that of the rest month’s savings of ₹ 6000 per month in the year. What is his average expenditure per month?Solution
Earning in the remaining 8 months = 8000 × 8 = ₹ 64000 Earning in March, May, July, December (4 months) = (8000 × 7/4) × 4 = ₹ 56000 ⇒ Total earnings (12 months) = 64000 + 56000 = ₹ 120000 Savings in the remaining 8 months = 6000 × 8 = ₹ 48000 Savings in March, May, July, and December (4 months) = (6000 × 3/2) × 4 = ₹ 36000 ⇒ Total savings (12 months) = 48000 + 36000 = ₹ 84000 ∴ Total expenditure (12 months) = 120000 - 84000 = ₹ 36000 ⇒ Average expenditure per month = 36000/12 = ₹ 3000
The minimum value of 45 sin2 θ + 28 cos2 θ is
Evaluate the following:
sin 60° × cos 30° + sin 30° × cos 60°
If 4sin² θ = 3(1+ cos θ), 0° < θ < 90°, then what is the value of (2tan θ + 4sinθ - secθ)?
- If 2cos²A + 3sin²A = 13/5, then find the value of (sec²A - 1)
- If sin (a + b) = (√3/2) and cos (a – b) = (√3/2), then find sin a.
sin2 17˚ + sin2 19˚ + sin2 21˚ + sin2 23˚ + ……… + sin2 77˚ = ?
If tan² 45°- cos² 60° x sin 45° cos 45° cot 30°, then find the value of 'x'.
If SecA + TanA = 2√2 + 9, then find the value of Sin A + Cos A.
