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Let the six numbers be a, b, c, d, e, f. a + b = 2 
70 = 140 ....................... (i) e + f = 2 45 = 90 ........................ (ii) a+ b + c + d + e + f = 6 65 = 390 ........................(iii) We get the sum of third and fourth digit by subtracting (i) and (ii) from (iii) a+ b+ c + d + e + f – a – b – e - f = 390 – 140 – 90 =160 ∴ c + d = 160 ∴ Required average = = 80
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