Question
The average age of three children is 15 years. If their
ages are in the ratio 2:3:4. Find the age of the youngest child.Solution
Total age of three children = 15 × 3 = 45 years Let their ages be 2x, 3x and 4x respectively. => 2x + 3x + 4x = 45 => 9x = 45 => x = 5 Therefore the age of youngest child = 2 × 5 = 10 years
Three numbers a, b and c are co-prime to each other such that ab = 88 and bc = 33. Find the value of (a + b + c).
The greatest number, which when subtracted from 1063, gives a number exactly divisible by each of 15, 20, 30 and 35, is:
Find the difference between sum of digits of LCM and HCF of 16, 40 and 64.
Three numbers a, b and c are co-prime to each other such that ab = 70 and bc = 45. Find the value of (a + b + c).
- Three numbers are in the ratio 7:2:3 respectively. If the HCF of the numbers is 6, then find the LCM of the numbers.
Find the smallest number which when divided by 3, 4, 5 and 6 gives remainder ‘2’ in each case?
The LCM of two numbers is 4 times of their HCF. The sum of LCM and HCF is 280. If one of the number is 224, then the other number is:
Three numbers are in the ratio 5:3:2 respectively. If the HCF of the numbers is 4, then find the LCM of the numbers.
Sum of the two numbers is 49 and their HCF and LCM are 7 and 70, respectively. Find the sum of reciprocal of the given two numbers.
- What is the unit digit of the number 'A' obtained by subtracting the largest two-digit prime number from the least common multiple (LCM) of all single-digi...
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