Question
There are 5 consecutive odd and 3 consecutive even
numbers. The sum of five consecutive odd numbers is 120 and the lowest even number is 4 more than the twice of average of 5 consecutive odd number. Find the ratio between the lowest odd number and the highest even number?Solution
Let the consecutive odd number be x, x+2, x+4, x+6, x+8 x + x+2 + x+4 + x+6 + x+8 = 120 5x = 120 - 20 5x = 100 x = 20 Average of 5 consecutive odd number = 120/5 = 24 The lowest even number = (2 × 24) + 4 = 52 The even numbers are 52, 54 and 56. The ratio between the lowest odd number and the highest even number = 20 : 56 = 5 : 14
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