Question
The ages of 4 members of a family are in the year 2011
are βXβ,βX+6β,βX+12β and βX+18β. After some years Oldest among them was dead then average reduced by 2. After how many years from his death, the average age will same as in 2011?Solution
Average of all in 2011 = {X + (X+6) + (X+12) + (X+18)}/4 = (4X + 36)/4 = X + 9 Let the oldest die after N years, then average of three persons, {X + (X+6) + (X+12) + 3N}/3 = (X+9-2) (3X+18+3N)/3 = X+7 X+6+N = X+7 N = 1 years Let after another M years, their average will be equal to that in 2011. So, (3X+18+3N+3M)/3 = X+9 (3X + 18 + 3x1 + 3M)/3 = X+9 X + 6 +1 +M = X+9 M = 2 years
What will come in the place of question mark (?) in the given expression?
(63 - ?) Γ· 5 + β625 = 19 X (9 - 6)
- What will come in place of (?), in the given expression.
(4Β² + 6Β²) Γ 2 = ? What will come in the place of question mark (?) in the given expression?
(40/25) X 80 - ? = 45% of 300 - 5525.6% of 250 + √? = 119
1220 Γ· 61 Γ· 5 + 450 of 20% - 70 = β ?
Simplify the expression:
(5x + 15) / (xΒ² + 3x)
What will come in the place of question mark (?) in the given expression?Β
435 Γ· 29 X 792 Γ· 44 = β(? + 14) + 35 + 221 Γ· 17
...192.251 + 326.233 + 125.021 + 19.273 = ?
36% of 640 β 12.5% of 352 + 25% of 640 = ? β 48% of 432
Simplify the following expressions and choose the correct option.
18 * 15 - {3/5 of 250 + 72}
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