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Sum of five numbers = 6 × 8 = 48 Let the third number be x, Second number will be 3x, First number will be 6x According to the question, (48+6x+3x+x)/9=12 ; (48+10x)/9=12; x= (108-48)/10 x=6 ∴ the three numbers will be 6, 18 and 36 ∴ Difference of first and third no.= 36 – 6 = 30
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