Question
Find the sum of 12th terms of a geometric progression
whose 1st term is 8 and common ratio is 2.Solution
GP = Sn = a(rn – 1)/(r – 1) Where a = 12, r = 2 Sum of 12 terms = a(r8 – 1)/(r – 1) ⇒ 12 × [(28 – 1)/(2 – 1)] ⇒ 12 × [256 – 1] ⇒ 12 × 255 ⇒ 3060
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