Find the sum of all number divisible by 6 in between 50 to 200.
Here 1st term = a = 54 (which is the 1st term greater than 50 that is divisible by 6) The last term less than 200, which is divisible by 6 is 198 The number of terms in the in the AP; 54, 60, 66……..198 Here a = 54, d = 6 and number of terms = (198 – 54)/6 + 1 = 25 Sn = {n/2} [2a + (n – 1)d)] Sn = (25/2) [(2 x 54) + (24 x 6)] Sn = 3150
What is least number which when successively divided by 6, 4 and 4 leaves a remainder 5, 3 and 3 respectively?
417/414 = ?
If a = radic;( 3/2) , then radic; (1+a) + radic; (1-a) = ?
(0.04)-2.5= ?
If 2x = 3y = 6-z, then (1/x) + (1/y) + (1/z) =?
If 100.13 = 14 and ( 0.1)x = 140, then what is the value of x.
Value of (x7/x6)6/5 is:
Find the value of 56× 59÷ 514= ?
(0.36)-1.5= ?