Question
The ratio of the speed of boat ‘A’ in still water,
the speed of boat ‘B’ in still water and the speed of the current is 8:5:2, respectively. If the time taken by boat ‘A’ to travel (7D – 24) km downstream is equal to the time taken by boat ‘B’ to travel (D + 50) km upstream, then find the value of ‘D’.Solution
Let, the speeds of boat ‘A’ and boat ‘B’, in still water and the speed of the current be 8x km/hr, 5x km/hr and 2x km/hr, respectively. According to the question, (7D – 24)/(8x + 2x) = (D + 50)/(5x – 2x) Or, 21D – 72 = 10D + 500 Or, 11D = 572 Or, D = 52
A $ B means A X B, A & B means A - B, A % B means A ÷ B and A # B means A + B, then what is the value of 320 & 80 # 120 % 24 $ 50?
Statements:
V ≤ P < S = B; T < U ≤ I = B; N < J < T
Conclusions:
I. J > P
II. N < S
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