Question
A swimmer swims from a point A against a current for 5
minutes and then swims current for next 5 minutes and comes to the point B. If AB is 100meters, the speed of the current is (km/h).Solution
. Let the speed of boat in still water =B and speed of stream =S Distance covered by downstream speed in 5 minutes =(B+S) ×5/60 Distance covered by downstream speed in 5 minutes=(B-S) ×5/60 ATQ- 
S=6/10 =0.6km/h Speed of current =S= 0.6km/h
99.99% of 9.99 + 299.98% of 129.98 = ?2Â
(56.03 + 112.98) ÷ 13.211 = 89.9 – 25.23% of ?
139.88% of 119.89 + 1451.89 ÷ 6.01 - √196.01 = ? ÷ 3.01 + 215.98Â
1111.25 × 9.05 + 2323.23 × 9.05 – 2121.37 × 9.05 = ?
The interest received by investing Rs. 1200 for 2 years at compound interest of 20% p.a., compounded annually, was re-invested for 3 years at simple int...
3.992 + (3.01 × 2.98) + ? = 225.03
? = 49.83% of 39.72% of (45.011.99 – 4.98 2.04)
45.1298% of (14.032 - 75.98) + 27.87% of √40001 = 449.98% of 24.098 + ?Â
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
