Question
(3/7 of 1049.88 + 44.95% of 799.79) ÷ (√168.89 +
24.77% of 400.11) = ? What will be the approximate value of the following questions.Solution
(3/7 of 1049.88 + 44.95% of 799.79) ÷ (√168.89 + 24.77% of 400.11) = (3/7 of 1050 + 45% of 800) ÷ (√169 + 25% of 400) = [(3/7 × 1050) + (0.45 × 800)] ÷ (13 + 0.25 × 400) = [450 + 360] ÷ (13 + 100) = 810 ÷ 113 = 7.16 = 7 Answer: A
20% of 1500 – 75% of 200 = 125% of ?Â
24% of 150% of 500 + 140 = ? × 8Â
458.32 - 563.32 + 659.32 =?
What will come in the place of question mark (?) in the given expression?
(√1089 + 84 ÷ 2) % of 348 = 416 - ?
40% are the passing marks. A student gets 250 marks yet fails by 38 marks. What is the maximum marks?
(22.5 × 24) ÷ 40 + 51.50 = ? ÷ 5.25
36×?² + (25% of 208 +13) = 60% of 2400 + 17×18
What will come in the place of question mark (?) in the given expression?
√64 X 9 ÷ 3 + 12 X 3 = ? + 36(3/7) x 868 + 25% of 240 = (? + 65)
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