Question
(400.01% of 149.89) ÷ 49.97 = ?2 ÷ (95.98
÷ 31.99) What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)Solution
ATQ, (400.01% of 149.89) ÷ 49.97 = ?2 ÷ (95.98 ÷ 31.99) ?2 ÷ (96 ÷ 32) ~ (400% × 150) ÷ 50 ?2 ÷ 3 ~ 600 ÷ 50 ?2 ~ 12 × 3 ? ~ √36 ~ 6
Simplify the following trigonometric expression:
...
12 cos 68o cosec 22o - 3 cot 72o cot 18o- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
√65 of 14.97 + √50 = (12.02)2 - ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
181.87 ÷ 13.89 X 8.13 + ? = 11.852Â
`[(7.99)^2 - (13.001)^2 + (4.01)^3]^2=` ?
(24.88% of 4879.79) + 20.030 × 13.88 of 13.86 + 46.21 = ? + (13.22)²
(8.86)² × (15.01)² ÷ √624.99 = 9?
What approximate value should come in the place of (?) in the following questions?
42.98% of 849 + 18.45% of 1201 ≈ ?