Question
[√ (121.23) ÷ √
(12100.04)] × √ 80.95 = 3/10 + ? ÷ 4 What approximate value will come in place of question mark (?) in the given equations?Solution
[√ (121.23) ÷ √ (12100.04)] × √ 80.95 = 3/10 + ? ÷ 4 [√ (121) ÷ √ (12100)] × √ 81 = 3/10 + ? ÷ 4 => (11/110) × 9 = 3/10 + ?/4 => (1/10) × 9 = 3/10 + ?/4 => 9/10 = 3/10 + ?/4 => 6/10 = ?/4 => ? = 12/5
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