Question
[√ (121.23) ÷ √
(12100.04)] × √ 80.95 = 3/10 + ? ÷ 4 What approximate value will come in place of question mark (?) in the given equations?Solution
[√ (121.23) ÷ √ (12100.04)] × √ 80.95 = 3/10 + ? ÷ 4 [√ (121) ÷ √ (12100)] × √ 81 = 3/10 + ? ÷ 4 => (11/110) × 9 = 3/10 + ?/4 => (1/10) × 9 = 3/10 + ?/4 => 9/10 = 3/10 + ?/4 => 6/10 = ?/4 => ? = 12/5
7/11 × 1034 + 1(4/7) × 2401 = 1230 +?
140% of 9/8 of ? = 108% of 2800
4.56 + 56.4 + 64.5 = ? + 10.46
- What will come in the place of question mark (?) in the given expression?
?² = 28% of 35% of 4500 12.5% of (100 + ?) = 40
What will come in the place of question mark (?) in the given expression?
? = 12.5% of 25% of 20% of 1280 + 1248
(? + 180 + 13 × 6) ÷ 20 + 3.5 × 512 (1/3) = 82
Solve for the ?
What will come in the place of question mark (?) in the given expression?
(437 + ? - 167) x 2.5 = 875(22% of 1500 + 15% of 2200) = ? x 11