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Let the quantity of the wine in the cask originally be x litres Then, quantity of wine left in cask after 2 operations = [x {1 - (12/x)}2] litres Therefore, [x {1 - (12/x)}2/x] = 4/9 [1 - (12/x)}2] = (2/3)2 x = 36 Original quantity of cask = 36 litres
(8 x 9) ÷ 5 + ?2 = 23.4
1500 ÷ 15 + 1000 ÷ √100 + ? = 250 * 3
4.2 × 6.5 × 7.8 = ?
22 – 15 + 20 × 18 ÷ 6 – 34 = ?
1540 ÷ 7 - 184 ÷ 8 = ?
24 × ?2 – 11 × 4 = 1900
72 – 4(40 + 24 ÷ 6 × 6 – 4 × 4) + 40
216% of 350 + 273 = ?2 × 21
[(15)³ × (8)²] ÷ (90 × 6) = ?²