Question
A sum of ₹4,360 was to be divided among A, B, C, and D
in the ratio 3:4:5:8, but it was divided in the ratio 1/3:1/4:1/5:1/8. Was divided by mistake: which of the following statements will hold as a result.Solution
ATQ, The sum was to be divided in the ratio 3:4:5:8. Let the sum of A, B, C, and D is 3x,4x,5x, and 8x respectively. According to the question, we get 20x = 8720 x=436 so, we get A = 1308; B = 1744; C = 2180; D =3488 But by mistake it was divided in the ratio; 1/3: 1/4: 1/5: 1/8 By Equating, the ratio will be 40: 34: 24: 15. The new sum of A, B, C and D will be 40x, 30x, 24x and 15x respectively. Solving in the same way, we get A =3200, B = 2400, C = 1920 and D = 1200 So, we can say D got 2288 less.
I: x2 + 31x + 228 = 0
II: y2 + 3y – 108 = 0
I. x² - 33x + 270 = 0
II. y² - 41y + 414 = 0
I. 5x² + 17x + 6 = 0
II. 2y² + 11y + 12 = 0
...I. 195x² - 46x - 21 = 0
II. 209y² + 7y - 12 = 0
I. 3x2 - 16x - 12 = 0
II. 2y2 + 11y + 9 = 0
I. 8x² + 2x – 3 = 0
II. 6y² + 11y + 4 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 36x + 288 = 0
Equation 2: y² - 36y + 320 = 0
I. 27(p + 2) = 2p(24 – p)
II. 2q2 – 25q + 78 = 0
I. 5x² -14x + 8 = 0
II. 2y² + 17y + 36 = 0
What is the nature of the roots of the quadratic equation x² – 5x + 7 = 0 ?
