Question
If (x²+y²+z²)/(xy+yz+zx) = 1 Find (x+y)/z +
(y+z)/x + (z+x)/ySolution
let x = y = z = 2 x²+y²+z² = xy+yz+zx ⇒ (x+x)/x + (x+x)/x + (x+x)/x ⇒ 2 + 2 + 2 = 6
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