Question
If a + b + c = 10 and ab + bc + ca = 28, then find the value of a² + b² + c².
Solution
Since, (a+b+c) ² = a² + b² + c² + 2(ab+bc+ca) So, a² + b² + c² = (10) ² – 2 x 28 = 100 - 56 = 44
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