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    Question

    Find the largest 5-digit number that is divisible by 12,

    15, 18, and 24. Also, what is the remainder when this number is divided by 11?
    A 99960, remainder 9 Correct Answer Incorrect Answer
    B 99960, remainder 8 Correct Answer Incorrect Answer
    C 99980, remainder 7 Correct Answer Incorrect Answer
    D 99720, remainder 5 Correct Answer Incorrect Answer

    Solution

    Step 1: Find the Least Common Multiple (LCM) of 12, 15, 18, and 24. Prime factorization: 12 = 2┬▓ ├Ч 3 15 = 3 ├Ч 5 18 = 2 ├Ч 3┬▓ 24 = 2┬│ ├Ч 3 LCM = 2┬│ ├Ч 3┬▓ ├Ч 5 = 360. Step 2: Find the largest 5-digit number divisible by 360. The largest 5-digit number is 99999. Divide 99999 by 360: 99999 ├╖ 360 = 277.77 (take the integer part, 277). Multiply 277 by 360: 277 ├Ч 360 = 99720. Step 3: Find the remainder when 99720 is divided by 11. 99720 ├╖ 11 = 9065, remainder 5. Correct Option: d

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