Question
If x:y:z = 3:4:6, and (5x + 3z) = 132, then find the
value of '3y'.Solution
Let x = '3a' So, y = 3a X (4/3) = '4a' And z = 3a X (6/3) = '6a' ATQ; 3a X 5 + 6a X 3 = 132 Or, 15a + 18a = 132 So, 33a = 132 So, a = 4 So, required value = 4 X 4a = 4 X 3 X 4 = 48
More Algebra Questions
√323.89 × (3.20) ÷ 9.02 =?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
23.98% of 624.99 = 19.98% of ? + 14.98% of 639.99
Direction: Please solve the following expression and choose the closest option
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
12, 16, ?, 36, 52, 72
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(6859.01)1/3 × 10.11 × 14.47 ÷ 20.32 = ? + 45.022
33.33% of 809.891 + 66.66% of 212.91 = ?
Relevant for Exams:
