If the 14th term of an arithmetic series is 6 and 6th term is 14, then what is the 95th term?
T 14 = a+13d = 6 --------- I and T6 = a+5d = 14----------- II solving I & II, we get a = 19, d = - 1 T 95 = a + 94d = 19+94(-1) = - 75
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