Question
If the 14th term of an arithmetic series is 6 and 6th
term is 14, then what is the 95th term?Solution
T 14 Â = a+13d = 6 ---------Â I and T6 Â = a+5d = 14-----------Â Â Â Â II solving I & II, we get a = 19, d = - 1 Â T 95 Â = a + 94d = 19+94(-1) = - 75
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