New Click here to Enroll for SIDBI MSME Expert Classes by Experts

    Register

    Question

    When positive numbers x, y and z are divided by 31, the

    remainders are 17, 24 and 27, respectively. When (4x - 2y + 3z) is divided by 31, the remainder will be:
    A 9 Correct Answer Incorrect Answer
    B 16 Correct Answer Incorrect Answer
    C 8 Correct Answer Incorrect Answer
    D 19 Correct Answer Incorrect Answer

    Solution

    (4x – 2y + 32) is divided by 31 Remainder ? when the divisior is same as the previous divisior = for this we can assume that x = 17, y = 24 and z – 27 = 4x – xy + 32 = 68 – 48 81 =101/31 R = 8

    Practice Next

    Relevant for Exams: