Question
When positive numbers x, y and z are divided by 31, the
remainders are 17, 24 and 27, respectively. When (4x - 2y + 3z) is divided by 31, the remainder will be:Solution
(4x – 2y + 32) is divided by 31 Remainder ? when the divisior is same as the previous divisior = for this we can assume that x = 17, y = 24 and z – 27 = 4x – xy + 32 = 68 – 48 81 =  101/31 R = 8
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