Question
A carriage travelling in fog passed along a man who was walking @ 6 km/hr in the same direction. He could see the carriage for 8 minutes and it was visible to him upto a distance of 400 metres. What was the speed of the carriage?
More Algebra Questions
- If x 2 – 15x + 51 = 0, then determine the value of (x – 5) + {1/(x – 5)}.
- If p = 24 - q - r and pq + r(q + p) = 132, then find the value of (p² + q² + r²).
- If a + b = 56 and (a – b)² = 496, find the value of the product of a and b.
- If x = √7 + √6 and y = √7 - √6 , then the value of is (x2 + y2)/(x3 + y3).
- Find the value of the expression {(4096) n /4 × 8 3n + 1 }/{(512) n × 8 n – 1 }.
- If (a + b) = 7 and ab = 11, then find the value of (a² + b²).
- If x, y and z are real numbers such that (x-5)2+(y-7)2+(z-9)2= 0 then (x+y+z) is equal to
- Question 8
- if a2 + b2 + c2 = 2(4a -5b -9c)-122 , then a-b-c = ?
- If x = 15, find x5 - 16x4 + 16x3 - 16x2 + 16x - 16 = ?
Relevant for Exams:
Hey! Ask a query
Please enter email id
The email must be a valid email address.
Please enter Mobile Number
Please enter valid Mobile Number
Please enter your Doubt
According to the question Man walks in 1 hour = 6000 m In 8 minutes = 6000/60 ×8 = 800 m Carriage: 8 minutes = 1200 m (because, 400 + 800) 60 minutes = 1200/8 × 60 = 9000 ≈ 9 km/hr IXAMBEE Approach: d1/d2= S1/S2 1200/800 = S1/6 S1 = 9 Km/hr