Question
A carriage travelling in fog passed along a man who was
walking @ 6 km/hr in the same direction. He could see the carriage for 8 minutes and it was visible to him upto a distance of 400 metres. What was the speed of the carriage?Solution
According to the question Man walks in 1 hour = 6000 m In 8 minutes = 6000/60 ×8 = 800 m Carriage: 8 minutes = 1200 m (because, 400 + 800) 60 minutes = 1200/8 × 60 = 9000 ≈ 9 km/hr IXAMBEE Approach: d1/d2= S1/S2 1200/800 = S1/6 S1 = 9 Km/hr
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (β 484 β β 256) = ?
(13)2Β - 3127 Γ· 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 Γ· 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 Γ 5 - {272 + 162 - 422}
(15 Γ 225) Γ· (45 Γ 5) + 480 = ? + 25% of 1240
β [? x 11 + (β 1296)] = 16
11 Γ 25 + 12 Γ 15 + 14 Γ 20 + 15 = ?