Question
7 years ago from now, the average age of βMβ and
βNβ was 27 years. The ratio of present age of βMβ and βOβ is 3:5, respectively. If βOβ is 4 years younger than βNβ, then find the age of βNβ 7 years hence from now.Solution
Let the present age of βMβ and βOβ be 3x years and 5x years respectively. So, the present age of βNβ = (5x + 4) years Sum of the ages of βMβ and βNβ 7 years ago from now = 27 X 2 = 54 years Sum of the present age of βMβ and βNβ = 54 + 14 = 68 years ATQ, (3x + 5x + 4) = 68 Or, 8x = 64 So, βxβ = 8 So, the present age of βNβ = 5 X 8 + 4 = 44 years Therefore, required age = 44 + 7 = 51 years
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