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      Question

      7 years ago from now, the average age of β€˜M’ and

      β€˜N’ was 27 years. The ratio of present age of β€˜M’ and β€˜O’ is 3:5, respectively. If β€˜O’ is 4 years younger than β€˜N’, then find the age of β€˜N’ 7 years hence from now.
      A 47 years Correct Answer Incorrect Answer
      B 49 years Correct Answer Incorrect Answer
      C 51 years Correct Answer Incorrect Answer
      D 53 years Correct Answer Incorrect Answer
      E 55 years Correct Answer Incorrect Answer

      Solution

      Let the present age of β€˜M’ and β€˜O’ be 3x years and 5x years respectively. So, the present age of β€˜N’ = (5x + 4) years Sum of the ages of β€˜M’ and β€˜N’ 7 years ago from now = 27 X 2 = 54 years Sum of the present age of β€˜M’ and β€˜N’ = 54 + 14 = 68 years ATQ, (3x + 5x + 4) = 68 Or, 8x = 64 So, β€˜x’ = 8 So, the present age of β€˜N’ = 5 X 8 + 4 = 44 years Therefore, required age = 44 + 7 = 51 years

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