Question
The present age of A is twice that of
B. Eight years ago, the ratio of their ages was 5 : 2. Find B's present age.
Solution
ATQ, Let B's present age = x A's present age = 2x Eight years ago: (2x - 8)/(x - 8) = 5/2 2(2x - 8) = 5(x - 8) 4x - 16 = 5x - 40 x = 24 This does not match options, so check again: 4x - 16 = 5x - 40 x = 24 So B's present age = 24 years
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