Question
Present age of 'B' is five times more than the age of
his brother. If two years ago, their ages were in ratio 10:1, respectively, then find the present age of 'B'.Solution
Let the present age of B's brother be 'x' years. So, present age of 'B' = x * 6 = '6x' years ATQ; {(6x - 2)/(x - 2)} = (8/1) Or, 6x - 2 = 8 * (x - 2) Or, 6x - 2 = 8x - 16 Or, 14 = 2x So, x = 7 So, present age of 'B' = 6 * 7 = 42 yearsÂ
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