Question
Present age of βMβ is 25% more than that of βNβ.
5 years ago, βMβ was 1.5 times as old as βNβ. Find the present age of βNβ.Solution
Let the present age of βNβ be βxβ years
Therefore, present age of βMβ = 1.25x years
ATQ;
(1.25x β 5) = 1.5 Γ (x β 5)
Or, 1.25x β 5 = 1.5x β 7.5
Or, 2.5 = 0.25x
Or, x = 10
Therefore, present age of βNβ = 10 years
I. 2x2 - 9 x + 9 = 0Β
II. 2y2 - 7 y + 3 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
I. 2xΒ² - 15x Β + 13 = 0
II. 3yΒ² - 6y + 3 = 0
I. xΒ²= 961Β
II. y= β961
If a quadratic polynomial y = ax2 + bx + c intersects x axis at a and Ξ², then
I. 27x6-152x3+125=0
II. 216y6Β -91y3+8=0
I. 4x² - 21x + 20 = 0
II. 8y² - 22y + 15 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 3xΒ² + 6x - 9 = 0
Equation 2: 2yΒ² - 16y + 32 = 0
I. 3pΒ²Β + 13p + 14 = 0
II. 8qΒ²Β + 26q + 21 = 0
I. 24x² - 58x + 23 = 0
II. 20y² + 24y – 65 = 0