Question
Present age of βMβ is 25% more than that of βNβ.
5 years ago, βMβ was 1.5 times as old as βNβ. Find the present age of βNβ.Solution
Let the present age of βNβ be βxβ years
Therefore, present age of βMβ = 1.25x years
ATQ;
(1.25x β 5) = 1.5 Γ (x β 5)
Or, 1.25x β 5 = 1.5x β 7.5
Or, 2.5 = 0.25x
Or, x = 10
Therefore, present age of βNβ = 10 years
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