Question
Present age of βSβ is 50% more than that of βTβ.
6 years ago, βSβ was 2.5 times as old as βTβ. Find the present age of βTβ.Solution
Let the present age of βTβ be βxβ years
Therefore, present age of βSβ = 1.5x years
ATQ;
(1.5x β 6) = 2.5 Γ (x β 6)
Or, 1.5x β 6 = 2.5x β 15
Or, 9 = x
Therefore, present age of βTβ = 9 years
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