Question
The average of the present ages of R, S and T is 28 years.
Triple the present age of S is 45 more than twice the present age of R. If Tβs age after 6 years will be 25% higher than his current age, determine the present age of R.Solution
ATQ,
Present age of T = 6 / 0.25 = 24 years
Let present ages of R and S be r and s, respectively.
So, r + s = 28 Γ 3 β 24 = 60 β¦β¦β¦β¦β¦β¦(1)
And, 3s β 2r = 45 β¦β¦β¦β¦β¦β¦(2)
Equation (1) Γ 3 β Equation (2), we get
3r + 3s β 3s + 2r = 60 Γ 3 β 45
Or, 5r = 135
Or, r = 27
So, present age of R = 27 years
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