Question
The average of the present ages of R, S and T is 28 years.
Triple the present age of S is 45 more than twice the present age of R. If T’s age after 6 years will be 25% higher than his current age, determine the present age of R.Solution
ATQ,
Present age of T = 6 / 0.25 = 24 years
Let present ages of R and S be r and s, respectively.
So, r + s = 28 × 3 – 24 = 60 ………………(1)
And, 3s – 2r = 45 ………………(2)
Equation (1) × 3 – Equation (2), we get
3r + 3s – 3s + 2r = 60 × 3 – 45
Or, 5r = 135
Or, r = 27
So, present age of R = 27 years
Statements:
A ≤ B < D < I; O > W > Z > B = I;
Conclusions:
I) B > O
II) B > A
Which of the following terms will replace the question mark (?) in the given series?
NQLM, OSMO, PUNQ, QWOS, ?
Statements: L ≥ M = N > O, R < M ≤ P > Q
Conclusion:
I. O ≥ Q
II. R < L
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