Question
The average of the present ages of R, S and T is 28 years.
Triple the present age of S is 45 more than twice the present age of R. If T’s age after 6 years will be 25% higher than his current age, determine the present age of R.Solution
ATQ,
Present age of T = 6 / 0.25 = 24 years
Let present ages of R and S be r and s, respectively.
So, r + s = 28 × 3 – 24 = 60 ………………(1)
And, 3s – 2r = 45 ………………(2)
Equation (1) × 3 – Equation (2), we get
3r + 3s – 3s + 2r = 60 × 3 – 45
Or, 5r = 135
Or, r = 27
So, present age of R = 27 years
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