Question
The sum of the present ages of a father and his daughter
is 80 years. Eight years ago, the fatherâs age was seven times the age of his daughter. Eight years from now, what will be the daughterâs age?Solution
ATQ,
Let daughterâs age = D Then fatherâs age = 80âD 8 years ago: 
Therefore, from 8 years from now = D+8 = 16+8 = 24 â
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