Question
The sum of the present ages of a father and his daughter
is 80 years. Eight years ago, the father’s age was seven times the age of his daughter. Eight years from now, what will be the daughter’s age?Solution
ATQ,
Let daughter’s age = D Then father’s age = 80−D 8 years ago: 
Therefore, from 8 years from now = D+8 = 16+8 = 24 ​
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