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    Question

    β€˜B’ is 14 years older than β€˜A’, and β€˜A’ is

    24 years younger than β€˜C’. Twelve years from now, the age of β€˜C’ will be 25% more than the age of β€˜A’. If the average of the present ages of β€˜A’ and β€˜D’ is 85 years, find the ratio of the ages of β€˜B’ to β€˜D’, 6 years ago.
    A 30:31 Correct Answer Incorrect Answer
    B 23:20 Correct Answer Incorrect Answer
    C 42:51 Correct Answer Incorrect Answer
    D 25:27 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ,

    Let present age of β€˜C’ be β€˜x’ years. Present age of β€˜A’ = x – 24 Present age of β€˜B’ = (x – 24) + 14 = x – 10 Twelve years hence: 1.25 Γ— [(x – 24) + 12] = x + 12 β‡’ 1.25 Γ— (x – 12) = x + 12 β‡’ 1.25x – 15 = x + 12 β‡’ 0.25x = 27 β‡’ x = 108 Present age of β€˜B’ = 108 – 10 = 98 years Present age of β€˜A’ = 108 – 24 = 84 years Average(A, D) = 85 β‡’ (A + D)/2 = 85 β‡’ D = 170 – 84 = 86 years Required ratio (6 years ago) = (98 – 6) : (86 – 6) = 92 : 80 = 23 : 20

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