ЁЯУв Too many exams? DonтАЩt know which one suits you best? Book Your Free Expert ЁЯСЙ call Now!
  • google app store apple app store
    • тЬЦ

      Question

      Five years ago, the average age of a family of

      four members was 25 years. Six years hence, the ratio of their ages will be 9:7:5:3. Find the approximate present ages of each family member.
      A A: 48 years, B: 36 years, C: 24 years, D: 12 years Correct Answer Incorrect Answer
      B A: 27 years, B: 21 years, C: 15 years, D: 9 years Correct Answer Incorrect Answer
      C A: 29 years, B: 23 years, C: 17 years, D: 11 years Correct Answer Incorrect Answer
      D A: 25 years, B: 27 years, C: 18 years, D: 5 years Correct Answer Incorrect Answer
      E A: 30 years, B: 24 years, C: 18 years, D: 12 years Correct Answer Incorrect Answer

      Solution

      Let the ages of the four family members be A, B, C, and D, respectively. Five years ago, the average age of a family of four members was 25 years: The total age of the family five years ago = 4 ├Ч 25 = 100 The sum of their ages five years ago = A + B + C + D = 100 The total present age of the family = (A + 5) + (B + 5) + (C + 5) + (D + 5) = 100+20 =120 Six years hence, The total age of the family =(A+5+6) + (B+5+6) + (C+5+6) + (D+5+6) = 120+24 =144 Six years hence, the ratio of their ages will be 9:7:5:3 (9x) + (7x) + (5x) + (3x) = 144 x = 144 / 24 x = 6 A = 9x тАУ 6 = (9 ├Ч 6) - 6 = 54 тАУ 6 = 48 years B = 7x тАУ 6 = (7├Ч 6) тАУ 6 = 42- 6 = 36 years C = 5x тАУ 6 = (5 ├Ч 6) - 6 = 30 тАУ 6 = 24 years D = 3x тАУ 6 = (3 ├Ч 6) - 6 = 18 тАУ 6 = 12 years

      Practice Next
      More Age Questions

      Relevant for Exams:

      ask-question