The current ages of Anita and Sunita are in a ratio of 3:4. If, four years from now, Sunita's age will be 20% greater than her current age, the question is to determine how many years younger Anita is than Sunita.
We can say that let the present ages of ‘Anita’ and ‘Sunita’ be ‘3y’ years and ‘4y’ years respectively. ATQ; 4y + 4 = 4y × 1.2 Or, 4y + 4 = 4.8y Or, 4 = 0.8y So, y = 5 So, present age of ‘Sunita’ = 4 × 5 = 20 years Present age of ‘Anita’ = 3 × 5 = 15 years Therefore, ‘Anita’ is (20 – 15) i.e. 5 years younger than ‘Sunita’
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