Question
Five years ago from now, the ages of 'A' and 'B' were in
the ratio 31:17, respectively. Fifteen years ago from now, the ages of 'A' and 'B' were in the ratio 3:1. Present age of 'A' is how much percent more than that of 'B'?Solution
Let the ages of 'A' and 'B', 15 years ago from now was, '3x' years and 'x' years, respectively. ATQ; {(3x + 10)/(x + 10)} = (31/17) Or, 17 × (3x + 10) = 31 × (x + 10) Or, 51x + 170 = 31x + 310 Or, 20x = 140 So, x = 7 So, present age of 'A' = 3 × 7 + 15 = 36 years And present age of 'B' = 7 + 15 = 22 years So, required percentage = {(36 - 22)/22} × 100 = 63.63%
612, 487,?, 396, 388, 387
Find the missing number in the given number series.
1, 2, 6, 24, 120, ?What will come in place of the question mark (?) in the following series?
36, 85, ?, 230, 330, 451
Find the missing term in the series:
2, 5, 11, 23, 47, ?
What will come in place of the question mark (?) in the following series?
400, 841, 1202, ?, 1716, 1885
44   45    41   50    ?      59    23
...221, 100, 0, -81, ?
...900 Â Â Â 90Â Â Â 18Â Â Â ? Â Â Â Â 2.16Â Â Â Â 1.08
16, 20, 11, 27, ?, 38
37, 57, 82, ?, 147, 187
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