Five years ago from now, the ages of 'A' and 'B' were in the ratio 31:17, respectively. Fifteen years ago from now, the ages of 'A' and 'B' were in the ratio 3:1. Present age of 'A' is how much percent more than that of 'B'?
Let the ages of 'A' and 'B', 15 years ago from now was, '3x' years and 'x' years, respectively. ATQ; {(3x + 10)/(x + 10)} = (31/17) Or, 17 × (3x + 10) = 31 × (x + 10) Or, 51x + 170 = 31x + 310 Or, 20x = 140 So, x = 7 So, present age of 'A' = 3 × 7 + 15 = 36 years And present age of 'B' = 7 + 15 = 22 years So, required percentage = {(36 - 22)/22} × 100 = 63.63%
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