Question
Five years ago from now, the ages of 'A' and 'B' were in
the ratio 31:17, respectively. Fifteen years ago from now, the ages of 'A' and 'B' were in the ratio 3:1. Present age of 'A' is how much percent more than that of 'B'?Solution
Let the ages of 'A' and 'B', 15 years ago from now was, '3x' years and 'x' years, respectively. ATQ; {(3x + 10)/(x + 10)} = (31/17) Or, 17 × (3x + 10) = 31 × (x + 10) Or, 51x + 170 = 31x + 310 Or, 20x = 140 So, x = 7 So, present age of 'A' = 3 × 7 + 15 = 36 years And present age of 'B' = 7 + 15 = 22 years So, required percentage = {(36 - 22)/22} × 100 = 63.63%
(22 × 52 ) + 4 × 6 = ? - √324
What should come in place of (?) question mark in the given expression.
 (25% of 320) + (3/8 of 400) − 30 = ?
(5832)1/3  × 10.11 × 11.97 ÷ 16.32 = ? + 45.022
82% of 400 + √(?) = 130% of 600 - 85% of 400
If (x + 1/x) = 5, then value of x3 + 1/x3 is:
Simplify: (1 ÷ 0.08)
What should come in place of (?) question mark in the given expression.
{ (144 ÷ 12) × 5 } − (18 ÷ 3) = ?
Simplify the following expressions and choose the correct option.
(3/4 of 256) + (2/5 of 150) - (72 ÷ 7)
464 + 181 +? = (154 × 25) - (15) 2 Â
15% of 1800 + 22 = ?Â
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