Question
Present ages of 'A' and 'B' are in the ratio 3:5,
respectively. If B's age, 12 years hence from now will be 9 times of A's age, 6 years ago from now, then find the present age of 'A'.Solution
Let the present ages of 'A' and 'B' be '3x' years and '5x' years, respectively. ATQ; (5x + 12) = 9 x (3x - 6) Or, 5x + 12 = 27x - 54 Or, 22x = 66 Or, x = 3 So, present age of 'A' = 3 x 3 = 9 years
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