Question
Present age of ‘A’ is 40% more than that of ‘B’.
If 25 years hence from now, ‘B’ will be 15 years younger than ‘A’, then find the sum of present ages of ‘A’ and ‘B’.Solution
Let present age of ‘B’ be ‘x’ years Present age of ‘A’ = x × 1.40 = ‘1.40x’ years ATQ; (x + 25) + 15 = (1.40x + 25) Or, x + 40 = 1.40x + 25 Or, 15 = 0.40x Or, x = 37.5 So, present age of ‘B’ = 37.5 years And, present age of ‘A’ = 37.5 + 15 = 52.5 years Required sum = 37.5 + 52.5 = 90 years
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