Question
Present age of βAβ is 40% more than that of βBβ.
If 25 years hence from now, βBβ will be 15 years younger than βAβ, then find the sum of present ages of βAβ and βBβ.Solution
Let present age of βBβ be βxβ years Present age of βAβ = x Γ 1.40 = β1.40xβ years ATQ; (x + 25) + 15 = (1.40x + 25) Or, x + 40 = 1.40x + 25 Or, 15 = 0.40x Or, x = 37.5 So, present age of βBβ = 37.5 years And, present age of βAβ = 37.5 + 15 = 52.5 years Required sum = 37.5 + 52.5 = 90 years
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
? = 41.92% of 49.96% of (45.07 1.97 β 4.98 2.03 )
(15.15Β Γ Β 31.98) + 30.15% of 719.99 = ? + 124.34
15.2 x 1.5 + 258.88+ ? = 398.12 + 15.9
784.69 + 86.96Β Γ· 29.01 = 40.01 + ? + 367.88
(29.892 Γ β290) + 32.98 Γ 6.91 = ?
(15.87% of 79.98 + 19.69% of 64.22) Γ 4.83 = ?
Β (3/5) of 3025 + (18Β² + 12Β²) = ? + 22.22% of 1125
24.75% of 20.125% of 30.05% of 2196.06 = ?Β
(799.81/64) ÷ (10/799.92) × (129.84/130) = ?
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