Question
Present age of βAβ is 50% more than that of βBβ. If 12 years hence from now, βBβ will be 7 years younger than βAβ, then find the sum of present ages of βAβ and βBβ.
Solution
Let present age of βBβ be βxβ years Present age of βAβ = x Γ 1.50 = β1.50xβ years ATQ; (x + 12) + 7 = (1.50x + 12) Or, x + 19 = 1.50x + 12 Or, 7 = 0.50x Or, x = 14 So, present age of βBβ = 14 years And, present age of βAβ = 14 + 7 = 21 years Required sum = 14 + 21 = 35 years
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