Question
Present age of βAβ is 25% more than that of βBβ.
If 9 years hence from now, βBβ will be 6 years younger than βAβ, then find the sum of present ages of βAβ and βBβ.Solution
Let present age of βBβ be βxβ years Present age of βAβ = x Γ 1.25 = β1.25xβ years ATQ; (x + 9) + 6 = (1.25x + 9) Or, x + 15 = 1.25x + 9 Or, 6 = 0.25x Or, x = 24 So, present age of βBβ = 24 years And, present age of βAβ = 24 + 6 = 30 years Required sum = 30 + 24 = 54 years
6, 8, 15, 44, ?, 1134.
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