Present age of ‘A’ is 25% more than that of ‘B’. If 9 years hence from now, ‘B’ will be 6 years younger than ‘A’, then find the sum of present ages of ‘A’ and ‘B’.
Let present age of ‘B’ be ‘x’ years Present age of ‘A’ = x × 1.25 = ‘1.25x’ years ATQ; (x + 9) + 6 = (1.25x + 9) Or, x + 15 = 1.25x + 9 Or, 6 = 0.25x Or, x = 24 So, present age of ‘B’ = 24 years And, present age of ‘A’ = 24 + 6 = 30 years Required sum = 30 + 24 = 54 years
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