Question
Present age of ‘A’ is 25% more than that of ‘B’.
If 9 years hence from now, ‘B’ will be 6 years younger than ‘A’, then find the sum of present ages of ‘A’ and ‘B’.Solution
Let present age of ‘B’ be ‘x’ years Present age of ‘A’ = x × 1.25 = ‘1.25x’ years ATQ; (x + 9) + 6 = (1.25x + 9) Or, x + 15 = 1.25x + 9 Or, 6 = 0.25x Or, x = 24 So, present age of ‘B’ = 24 years And, present age of ‘A’ = 24 + 6 = 30 years Required sum = 30 + 24 = 54 years
111   113   117   120   ?   133
If  7     43    x     1311    5247       15739
Then, x - x/2 + 2 = ?
...4 12 ? 144 544 2112
...25 13.5 12.5 20.75 39.5 ? 302.25
...4Â Â Â Â Â Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â Â Â Â Â Â 24Â Â Â Â Â Â Â Â Â Â Â 91Â Â Â Â Â Â Â Â Â Â Â 462Â Â Â Â Â Â Â Â Â 2763
18Â Â Â ...
7Â Â Â Â Â Â Â Â Â Â Â 26Â Â Â Â Â Â Â Â Â Â Â Â Â Â 238Â Â Â Â Â Â Â Â Â Â Â Â Â Â 962Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 8522Â Â Â Â Â Â Â Â Â Â Â Â Â ...
24 25 46 ? 572 2885
...29    51    95    183    ?     711
3 15 35 63 99 ?
3,   2,   3,  8,  31,  ?
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