Question
The present age of A is 7/5 times to that of his
marriage age. Present age of his brother is 1/2nd of his present age. If A was married 20 years ago then find the present age of his brother.Solution
Let the age of A when he was married be x years. Present age of A = 7x/5 Present age of his brother = (1/2) × (7x/5) = 7x/10 According to Question, => x + 20 = 7/5x => 2/5x = 20 => x = 50 years Present age of his brother = (7/10) × 50 = 35 years
More Age Questions
1290, 1225, 1175, ?, 1112, 1095, 1085
48   49    45     54    ?      63      27
...√(10198 )× √(7220 )÷ 16.69 + 2010.375= ?
4, 4, 12, 60, ?, 3780
4    9    28    99    ?   2105   12660
...12, 27, ?, 113, 141, 285, 313
What will come in place of (?) Question mark in the given number series.
1, 2, 5, 14, 41, 122, ?
16.12 × 15.94 + 654.92 – 344.83 = ?× 5.95
306, 272, 240, ?, 182, 156
728, 737, ?, 778, 814, 863Â
