The present age of A is 7/5 times to that of his marriage age. Present age of his brother is 1/2nd of his present age. If A was married 20 years ago then find the present age of his brother.
Let the age of A when he was married be x years. Present age of A = 7x/5 Present age of his brother = (1/2)×(7x/5) = 7x/10 According to Question, => x + 20 = 7/5x => 2/5x = 20 => x = 50 years Present age of his brother = (7/10) ×50 = 35 years
(-251 × 21 × -12) ÷ ? = 158.13
? = (25% of 20% of 800) × 8 – 25% of 260
350% of (450 / 1.5) = ?% of 4200
10 × 100 ÷ 5 + 9 = ?
4567.89 - 567.89 - 678.89 = ?
72.5% of 400 – 23.25% of 1020 = 105% of ?
116*2/3% of 18600 + 666*2/3% of 1290 = 457*1/7% of 1750 + 555*5/9% of 3150 + ?
50 ÷ 2.5 × 64 + ? = 1520
√3598 × √(230 ) ÷ √102= ?
(√196 + √121) × 4 = ?/2