Question
The ratio of the present ages of father and his son is
7:3. The product of their ages 3 years ago was 32 times of his son’s age that year. What was son’s age 2 year ago?Solution
Let present age of father and son be 7x and 3x respectively. According to question,  => (7x – 3) (3x – 3) = 32 × (3x – 3)  => (7x – 3) = 32 => 7x = 35 => x = 5 Therefore, son’s age 2 years ago = (3x – 2) = 13 years
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