Question
The ratio of the present ages of βAβ and βBβ is
3:4, respectively. Two years hence from now, the age of βBβ will be 10 years. If the average of present ages of βAβ, βBβ and βCβ is 22 years, then find the present age of βCβ.Solution
Let the present ages of βAβ and βBβ be 3x years and 4x years, respectively Therefore, 4x + 2 = 10 Or, 2x = 8 Or, x = 4 Sum of present ages of βAβ and βBβ = 3x + 4x = 14 years Sum of present ages of βAβ, βBβ and βCβ = 22 Γ 3 = 66 years Therefore, present age of βCβ = 66 β 14 = 52 years
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