Question
The ratio of the present ages of ‘A’ and ‘B’ is 3:4, respectively. Two years hence from now, the age of ‘B’ will be 10 years. If the average of present ages of ‘A’, ‘B’ and ‘C’ is 22 years, then find the present age of ‘C’.
Solution
Let the present ages of ‘A’ and ‘B’ be 3x years and 4x years, respectively Therefore, 4x + 2 = 10 Or, 2x = 8 Or, x = 4 Sum of present ages of ‘A’ and ‘B’ = 3x + 4x = 14 years Sum of present ages of ‘A’, “B’ and ‘C’ = 22 × 3 = 66 years Therefore, present age of ‘C’ = 66 – 14 = 52 years
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