Question
The ages of A, B and C together are 62 years. B is twice
as old as A and C is 6 years older than A. What is the difference between ages of B and C?Solution
Let A’s age be x years. B’s age = 2x and C’s age = (6 + x) According to question, => x + 2x + (6 + x) = 62 => 4x = 56 => x = 14 B’s age = 2x = 28 years C’s age = 6 + x = 20 years Difference between the ages of B and C = 28 – 20 = 8 years
(22 × 52 ) + 4 × 6 = ? - √324
What should come in place of (?) question mark in the given expression.
 (25% of 320) + (3/8 of 400) − 30 = ?
(5832)1/3  × 10.11 × 11.97 ÷ 16.32 = ? + 45.022
82% of 400 + √(?) = 130% of 600 - 85% of 400
If (x + 1/x) = 5, then value of x3 + 1/x3 is:
Simplify: (1 ÷ 0.08)
What should come in place of (?) question mark in the given expression.
{ (144 ÷ 12) × 5 } − (18 ÷ 3) = ?
Simplify the following expressions and choose the correct option.
(3/4 of 256) + (2/5 of 150) - (72 ÷ 7)
464 + 181 +? = (154 × 25) - (15) 2 Â
15% of 1800 + 22 = ?Â