Question
The ages of A, B and C together are 62 years. B is twice
as old as A and C is 6 years older than A. What is the difference between ages of B and C?Solution
Let A’s age be x years. B’s age = 2x and C’s age = (6 + x) According to question, => x + 2x + (6 + x) = 62 => 4x = 56 => x = 14 B’s age = 2x = 28 years C’s age = 6 + x = 20 years Difference between the ages of B and C = 28 – 20 = 8 years
41.66% of 888 + 66.66% of 1176 = ?2 - 4√ 16 Â
Evaluate: 320 − {18 + 4 × (21 − 9)}
Simplify: 72 ÷ 6 × 3 − 8 + 4
118 × 6 + 13 + 83 = ?
Simplify the following expression:
  (400 +175) ² - (400 – 175) ² / (400 × 175)
150% of 850 ÷ 25 – 25 = ?% of (39312 ÷ 1512)
(75 + 0.25 × 10) × 4 = ?2 - 14
26% of 650 + 15% of 660 – 26% of 450 = ?
115% of 40 + 3 × 4 = ? × 11 – 8