Question
What is the output of the following pseudo-code?Â
 ```   count = 0   for i from 1 to 3:     for j from 1 to i:       count = count + 1   print(count)   ```Solution
Dry Run: Â Â Â Â Â Â `count = 0` Â Â Â Â Â Â `i = 1`: Â Â Â Â Â Â Â Â `j = 1`: `count = 0 + 1 = 1` Â Â Â Â Â Â `i = 2`: Â Â Â Â Â Â Â Â `j = 1`: `count = 1 + 1 = 2` Â Â Â Â Â Â Â Â `j = 2`: `count = 2 + 1 = 3` Â Â Â Â Â Â `i = 3`: Â Â Â Â Â Â Â Â `j = 1`: `count = 3 + 1 = 4` Â Â Â Â Â Â Â Â `j = 2`: `count = 4 + 1 = 5` Â Â Â Â Â Â Â Â `j = 3`: `count = 5 + 1 = 6` Â Â Â Â Â Â Final `count = 6`Â
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