Question
What is the output of the following pseudo-code? ``` count = 0 for i from 1 to 3: for j from 1 to i: count = count + 1 print(count) ```
Solution
Dry Run: `count = 0` `i = 1`: `j = 1`: `count = 0 + 1 = 1` `i = 2`: `j = 1`: `count = 1 + 1 = 2` `j = 2`: `count = 2 + 1 = 3` `i = 3`: `j = 1`: `count = 3 + 1 = 4` `j = 2`: `count = 4 + 1 = 5` `j = 3`: `count = 5 + 1 = 6` Final `count = 6`
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