Question
Two identical spheres with charges +4q and –q are
brought into contact and then separated. What is the final force between them if their centers are r meters apart?Solution
Initial charges: · Sphere 1: +4q · Sphere 2: -q When identical conducting spheres are brought into contact: The total charge redistributes equally between the two spheres. Total charge calculation: Total charge = (+4q) + (-q) = +3q After contact and separation: Since the spheres are identical, the total charge splits equally: · Final charge on each sphere = (+3q)/2 = +1.5q So both spheres end up with charge +1.5q each. Using Coulomb's law: F = k|q₁q₂|/r² With both charges being +1.5q: F = k|(+1.5q)(+1.5q)|/r² F = k(1.5q)²/r² F = k(2.25q²)/r²
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