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ATQ, Time taken by 'A' alone to complete the entire work = 18 ÷ 0.6 = 30 days Time taken by 'B' alone to complete the entire work = 30 + 15 = 45 days Let the total work = L.C.M of 30, 45 and 20 = 180 units Then, efficiency of 'B' = (180/45) = 4 units/day Combined efficiency of 'B' and 'C' = (180/20) = 9 units/day So, efficiency of 'C' alone = 9 - 4 = 5 units/day So, time taken by 'C' alone to complete the entire work = (180/5) = 36 days
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