Question
Working individually, 'A' can finish 60% of a task in 18
days, and 'B' takes 15 days longer than 'A' to complete the entire task. However, 'B' and 'C' working together can complete the task in 20 days. Now, What will be the amount of time 'C' would need to complete the same task when working alone.Solution
ATQ, Time taken by 'A' alone to complete the entire work = 18 ÷ 0.6 = 30 days Time taken by 'B' alone to complete the entire work = 30 + 15 = 45 days Let the total work = L.C.M of 30, 45 and 20 = 180 units Then, efficiency of 'B' = (180/45) = 4 units/day Combined efficiency of 'B' and 'C' = (180/20) = 9 units/day So, efficiency of 'C' alone = 9 - 4 = 5 units/day So, time taken by 'C' alone to complete the entire work = (180/5) = 36 days
For knowing the cash (liquidity) position of a company which of the ratio will be used?
Which is the first Indian company to be listed in NASDAQ?
What is FCCB?
Which statement against the markets mentioned below is incorrect -
As per the recent guidelines regarding NBFCs (Non Banking Finance Companies), the NBFCs in Upper and Middle layer are required to implement Core Financi...
Reserve Bank of India has cancelled the license of Independence Co-operative Bank Ltd. It is based at ________________.
The most active segment of the Money Market in India is which one of the following?
What is CIBIL score?
Which of the market can be divided into primary and secondary market?
If a bond is issued when prevailing interest rates are 8% at Rs.1,000 par value with a 8% annual coupon. Which of the following is NOT correct?
...
Relevant for Exams:
