Question
A stone of mass 0.08 kg is thrown vertically upwards.
Give the direction and magnitude of the net force on the stone during its downward motion. Ignore air resistance.Solution
When the stone is moving in a downward direction, then the only force acting on the stone is the weight of the stone in the downward direction. Hence net force acting on the stone is the weight of the stone. Net force = 0.8 N
I. 3p² - 17p + 22 = 0
II. 5q² - 21q + 22 = 0
I. 3x2 – 17x + 10 = 0
II. y2 – 17y + 52 = 0
I. 35 y² + 58 y + 24 = 0
II. 21 x² + 37 x + 12 = 0
I. 5x2 – 7x – 6 =0
II. 2y2 – 5y – 7 =0
I. 40 x² - 93 x + 54 = 0
II. 30 y² - 61 y + 30 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 37x² - 172x + 135 = 0
Equation 2: 29y² - 132y + ...
I: x2Â + 31x + 228 = 0
II: y2 + 3y – 108 = 0
I. 14p2 – 135p + 81 = 0
II. 7q2 – 65q + 18 = 0
I. 64x2 - 64x + 15 Â = 0 Â Â Â Â
II. 21y2 - 13y + 2Â =0
I. 6y2 – 23y + 20 = 0
II. 4x2 – 24 x + 35 = 0
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