Question

    A metal surface has a threshold frequency of 4.0 ×

    10¹⁴ Hz.  When light of frequency 9.0 × 10¹⁴ Hz  is incident on it, what is the stopping potential required to halt the fastest photoelectrons? (Take h = 6.63 × 10⁻³⁴ Js, e = 1.6 × 10⁻¹⁹ C)
    A 1.25 V Correct Answer Incorrect Answer
    B 2.07 V Correct Answer Incorrect Answer
    C 3.56 V Correct Answer Incorrect Answer
    D 4.08 V Correct Answer Incorrect Answer

    Solution

    According to the photoelectric equation:

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