Question
A metal surface has a threshold frequency of 4.0 ×
10¹⁴ Hz. When light of frequency 9.0 × 10¹⁴ Hz is incident on it, what is the stopping potential required to halt the fastest photoelectrons? (Take h = 6.63 × 10⁻³⁴ Js, e = 1.6 × 10⁻¹⁹ C)Solution
According to the photoelectric equation:
Find the wrong number, in the given number series,
4, 10, 20, 40, 100, 250, 500
9 20 63 255 1285 7716
...Find the wrong number in the given number series.
2, 3, 5, 8, 13, 22, 34In each of the following giving number series, a wrong number is given. Find out the wrong number?
3023, 3132, 3246, 3356, 3471
547, 594, 640, 691, 741, 792
5, 13, 41, 185, 1111, 8149
2, 4, 16, 48, 240, 1440, 10080
Find the wrong number in the given number series.
3, 6, 24, 120, 720, 5040
12, 3.6, 18, 0.72, 0.432, 0.3024
24, 12, 22.5, 45, 157.5, 708.75