Question
A metal surface has a threshold frequency of 4.0 ×
10¹⁴ Hz. When light of frequency 9.0 × 10¹⁴ Hz is incident on it, what is the stopping potential required to halt the fastest photoelectrons? (Take h = 6.63 × 10⁻³⁴ Js, e = 1.6 × 10⁻¹⁹ C)Solution
According to the photoelectric equation: 
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