Answer-A 100 mL solution having 0.01 moles of NaOH dissolved in it. The pH of the solution is:

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To find the pH of the solution, we first need to calculate the concentration of hydroxide ions  OH- in the solution, since NaOH dissociates completely in water to produce OH- ions. Given that the solution contains 0.01 moles of NaOH dissolved in 100 mL of solution, we can calculate the molarity M of NaOH M moles of solute volume of solution in liters So, M  0.01 moles 0.1 L 0.1 . Since NaOH dissociates completely, the concentration of OH ions is equal to the molarity of NaOH OH-  0.1 M Now, to find the pOH of the solution, we use the formula POH  - log OH- POH  log0.1 POH  --1 POH  1 Finally, we can find the pH using the relation pH  pOH  14 pH  14-p pH  14-1 pH  13

A 100 mL solution having 0.01 moles of NaOH dissolved in

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