Question
Consider the following statements in regards to PRAGATI
Scheme for scholarship: 1. It has been launched by the MHRD from the year 2014-15 and implemented by CBSE. 2. It aimed at providing assistance for Advancement of Girls participation in Technical Education 3. It can be extended for 2 Girl Child per family where the family income is less than Rs. 8 Lakh per annum Which of the following statements is/are incorrect?Solution
To provide encouragement and support to Girl Child to pursue technical education “Pragati Scholarship” has been launched by the MHRD from the year 2014-15 and implemented by All India Council for Technical Education (AICTE). This is an attempt to give every young woman the opportunity to further her education and prepare for a successful future by “ Empowering Women Through Technical Education”. Number of scholarships per annum: 4000 ‘One Girl’ per family and it can be extended for Two Girl Child per family where the family income is less than Rs. 8 Lakh /annum (In case of married girl child, the income of parents/ in laws whichever is higher is to be considered). Amount of scholarship: Tuition Fee of Rs. 30000/- or at actual, whichever is less and Rs. 2000/- per month for 10 months as incidentals each year.
In the question, assuming the given statements to be true, find which of the following conclusion(s) among the two conclusions is/are true and then give...
Statements: A ≤ B = C ≥ D > E > F; F = G ≥ H = I > J > K = L
Conclusions:
I. B > F
II. H = L
Statement: M = C ≥ A = V < Q = S
Conclusions:
I. M ≥ V
II. A < S
Statements: Q % G & Z % G; G # C & E; E @ P # D
Conclusions : I. C @ P II. Q % P ...
Statements: O @ G % N & A @ I % P; V $ U & Q # A
Conclusions:
I. N @ U
II. G % V
III. V # I
Statements: X < H = U ≤ I < N = M, M > B ≥ V
Conclusions:
I. I > V
II. U ≥ MStatements:
R ≤ S = T; P < Q = R; S < U ≤ V; W ≥ V
Conclusions:
I). P < U
II). W > R
III). T ≥ Q...
Statements: L ≤ Y = T ≤ S; S = F ≤ U; K > N = U
Conclusions:
I. K > T
II. U ≥ L
...Statements: S > T > V ≤ W < X; V > P > U
Conclusions:
I. S > U
II. P < X
III. S > X
Statements: X > U < Y = W ≤ Z = S ≤ N ≥ T > I
Conclusions:
I. U ≥ Z
II. Y ≤ N
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